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8x^2+13x+11=-8x+5
We move all terms to the left:
8x^2+13x+11-(-8x+5)=0
We get rid of parentheses
8x^2+13x+8x-5+11=0
We add all the numbers together, and all the variables
8x^2+21x+6=0
a = 8; b = 21; c = +6;
Δ = b2-4ac
Δ = 212-4·8·6
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{249}}{2*8}=\frac{-21-\sqrt{249}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{249}}{2*8}=\frac{-21+\sqrt{249}}{16} $
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